Question 1186735: "A truck that hauls water is capable of carrying a maximum of 1600 lb. Water weighs
8.3454 lb/gal, and the plastic tank on the truck that holds water weighs 90 lb. Assume the truck can carry a maximum of gallons of water. Write an inequality to model this scenario. There is no need to solve it."
Answer by ikleyn(52776) (Show Source):
You can put this solution on YOUR website! .
"A truck that hauls water is capable of carrying a maximum of 1600 lb. Water weighs
8.3454 lb/gal, and the plastic tank on the truck that holds water weighs 90 lb.
Assume the truck can carry a maximum of gallons of water.
Write an inequality to model this scenario. There is no need to solve it."
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The requested inequality is
8.3454*G + 90 <= 1600 lb,
where G is the number of GALLONS.
Solved, explained and completed.
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