SOLUTION: A model rocket is launched upward with an initial velocity of 240 feet per second. The height, in feet, of the rocket t seconds after the launch is given by
h = −16t2 + 240t.
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h = −16t2 + 240t.
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Question 1186597: A model rocket is launched upward with an initial velocity of 240 feet per second. The height, in feet, of the rocket t seconds after the launch is given by
h = −16t2 + 240t.
How many seconds after the launch will the rocket be 340 feet above the ground? Round to the nearest tenth of a second. Answer by ikleyn(52785) (Show Source):
To answer the question, you need solve this quadratic equation
-16t^2 + 240t = 340.
You will get two roots: one works for ascending move; the other works for descending move.
ANSWER. t = 1.584 seconds; t = 13.42 seconds.
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