SOLUTION: John had only 10-dollar notes and David had only 5-dollar notes. The number of notes John had was 2/3 of the number of notes David had. After John had given David $450 in $10 not

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: John had only 10-dollar notes and David had only 5-dollar notes. The number of notes John had was 2/3 of the number of notes David had. After John had given David $450 in $10 not      Log On


   

Question 1186479: John had only 10-dollar notes and David had only 5-dollar notes. The number of notes
John had was 2/3 of the number of notes David had. After John had given David $450 in
$10 notes, the number of notes John had was 1/6 of the number of notes David had.
How much money did David have in the end?
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
                    Notes         Transfer John to David (45 notes)

John ($10)           j             j-45

David ($5)           d             d+45

                   j=(2/3)d        j-45=(1/6)(d+45)

Maybe easier to change those two equations:

system%283j=2d%2C6%28j-45%29=d%2B45%29

Simplify and solve the system and find how many notes each of John and David started with.
Compute the money for each. At the finish, John had $450 less; and David had $450 more.

Not the only method.