SOLUTION: Six consecutive odd integers have a sum of 12. Find the integers.

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Question 1186424: Six consecutive odd integers have a sum of 12. Find the integers.
Found 3 solutions by MathLover1, Alan3354, josgarithmetic:
Answer by MathLover1(20850) About Me  (Show Source):
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If x is an odd integer, then x+%2B+2, x+%2B+4,+x+%2B+6,x+%2B+8 and x%2B10 are six consecutive odd integers
x%2Bx+%2B+2%2Bx+%2B+4%2Bx+%2B+6%2Bx+%2B+8%2Bx%2B10=12
6x+%2B+30=12
6x+=12-30
6x+=-18
x+=-3
find other integers:
x+%2B+2=-3%2B2=-1
x+%2B+4=-3%2B4=1
+x+%2B+6=-3%2B6=3
x+%2B+8=-3%2B8=5
x%2B10=-3%2B10=7
then your integers are:
-3, -1,1,3,5,7

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Six consecutive odd integers have a sum of 12. Find the integers.
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The average is 12/6 = 2
So there are 3 odds <2, and 3 odds >2

Answer by josgarithmetic(39630) About Me  (Show Source):