SOLUTION: Mary spent 0.7 of her money on 15 mangoes
and 5 oranges, if each orange cost half as much
as a mango, how many oranges could she buy
with the rest of her money?
Algebra ->
Percentage-and-ratio-word-problems
-> SOLUTION: Mary spent 0.7 of her money on 15 mangoes
and 5 oranges, if each orange cost half as much
as a mango, how many oranges could she buy
with the rest of her money?
Log On
Question 1186268: Mary spent 0.7 of her money on 15 mangoes
and 5 oranges, if each orange cost half as much
as a mango, how many oranges could she buy
with the rest of her money? Found 2 solutions by ikleyn, josgarithmetic:Answer by ikleyn(52794) (Show Source):
You can put this solution on YOUR website! .
Mary spent 0.7 of her money on 15 mangoes and 5 oranges,
if each orange cost half as much as a mango,
how many oranges could she buy with the rest of her money?
~~~~~~~~~~~~~~~~
According to the condition, each mango costs as much as two oranges.
THEREFORE, 15 mango and 5 oranges cost as much as 2*15 + 5 = 30 + 5 = 35 oranges.
HENCE, each orange costs = 0.02 of the total Mary's money.
On the rest of her money she can buy = = 15 oranges.
ANSWER. On the rest of her money Mary can buy 15 oranges.
You can put this solution on YOUR website! ---------------------------------------------------
Mary spent 0.7 of her money on 15 mangoes
and 5 oranges, if each orange cost half as much
as a mango, how many oranges could she buy
with the rest of her money?
---------------------------------------------------
M amount of money
n, price of 1 Orange
2n, price of 1 mango
------------price of 1 orange --------------price for 1 mango --------------amount of money Mary has after the first described purchase.
The question:
Amount of oranges she can buy using the remaining 0.3M of money: