SOLUTION: log(base 10)y + log(base 10)(y+3)=1

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Question 118623This question is from textbook Glenco Mathematics Algebra 2
: log(base 10)y + log(base 10)(y+3)=1 This question is from textbook Glenco Mathematics Algebra 2

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
log(base 10)y + log(base 10)(y+3)=1
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log(base 10)[y(y+3)] = 1
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Change to exponential formL
y(y+3) = 10^1
y^2+3y-10 = 0
(y-5)(y+2) = 0
y = 5 or y = -2
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But y cannot be negative in the original equation
so y = 5 is the only solution.
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Cheers,
Stan H.