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Find two consecutive even integers that their sum is equal to the difference
of three times the larger and two times the smaller
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Taking the two consecutive even integers in the form n and (n+2),
we translate the problem into this Math equation the equation
n + (n+2) = 3*(n+2) - 2n.
Now we simplify and solve the equation
2n + 2 = 3n + 6 - 2n
2n + 2 = n + 6
2n - n = 6 - 2
n = 4
ANSWER. The pair of the numbers is (4,6).
Solved.