SOLUTION: Two cyclists start at the same point and travel in opposite directions. One cyclist travels 5 mi/h faster than the other. If the two cyclists are 155 miles apart after 5 hours, wha

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Two cyclists start at the same point and travel in opposite directions. One cyclist travels 5 mi/h faster than the other. If the two cyclists are 155 miles apart after 5 hours, wha      Log On


   

Question 1186103: Two cyclists start at the same point and travel in opposite directions. One cyclist travels 5 mi/h faster than the other. If the two cyclists are 155 miles apart after 5 hours, what is the rate of each cyclist?
Found 2 solutions by JBnovelwriter, MathTherapy:
Answer by JBnovelwriter(34) About Me  (Show Source):
You can put this solution on YOUR website!
5h%28x%28m%2Fh%29%2By%28m%2Fh%29%29=155m
y=x%28m%2Fh%29%2B5%28m%2Fh%29
5h%28x%28m%2Fh%29%2B%28x%28m%2Fh%29%2B5%28m%2Fh%29%29%29=155m
5h%28x%28m%2Fh%29%2Bx%28m%2Fh%29%2B5%28m%2Fh%29%29=155m
5h%282x%28m%2Fh%29%2B5%28m%2Fh%29%29=155m
5%282xm%2B5m%29=155m
10xm%2B25m=155m
10xm=130m
xm=13m
x=13 13m/hr
y=18 18m/hr

Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!

Two cyclists start at the same point and travel in opposite directions. One cyclist travels 5 mi/h faster than the other. If the two cyclists are 155 miles apart after 5 hours, what is the rate of each cyclist?
Let rate of slower cyclist be S

Then rate of faster cyclist = S + 5

We then get the following DISTANCE equation: 5S + 5(S + 5) = 155

S + S + 5 = 31 ------ Factoring out GCF, 5/Dividing by 5

2S = 26

Speed of slower cyclist, or highlight_green%28matrix%281%2C6%2C+S%2C+%22=%22%2C+26%2F2%2C+%22=%22%2C+13%2C+mph%29%29

You should now be able to find the faster cyclist's rate/speed.