SOLUTION: The length of a rectangle is five more than twice its width. The area of the rectangle is 52 square meters. Find the dimensions of the rectangle. (Applyong quadratic equations)

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: The length of a rectangle is five more than twice its width. The area of the rectangle is 52 square meters. Find the dimensions of the rectangle. (Applyong quadratic equations)      Log On


   

Question 1186014: The length of a rectangle is five more than twice its width. The area of the rectangle is 52 square meters. Find the dimensions of the rectangle. (Applyong quadratic equations)
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
w, the width
2w%2B5, the length
w%282w%2B5%29=52, the area

Apply quadratic equations?
More than one way to do.
Try maybe ((((2w)(2w+5)=2*52}}}, or %282w%29%282w%2B5%29=104; and MAYBE you might find two factors differing by five, whose product is 104.

Or try for factoring or general solution:
2w%5E2%2B5w-52=0
w=%28-5%2Bsqrt%285%5E2-4%2A2%2A%28-52%29%29%29%2F%282%2A2%29
w=%28-5%2Bsqrt%2825%2B416%29%29%2F%282%2A2%29
w=%28-5%2Bsqrt%28441%29%29%2F4
w=%28-5%2B21%29%2F4
w=16%2F4
highlight%28w=4%29