SOLUTION: Using the unit normal table, find the proportion under the standard normal curve that lies between each of the following: (a) the mean and z=0 (b) the mean and z =1.96 (c)

Algebra ->  Probability-and-statistics -> SOLUTION: Using the unit normal table, find the proportion under the standard normal curve that lies between each of the following: (a) the mean and z=0 (b) the mean and z =1.96 (c)      Log On


   

Question 1185988: Using the unit normal table, find the proportion under the standard normal curve that lies between each of the following:
(a) the mean and z=0
(b) the mean and z =1.96
(c) z= -1.50 and z= -1.50
(d) z= -.30 and z= -.10
(e) z= 1.00 and z= 2.00
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
i used the following table.

https://www.rit.edu/academicsuccesscenter/sites/rit.edu.academicsuccesscenter/files/documents/math-handouts/Standard%20Normal%20Distribution%20Table.pdf

in a normal distribution z-score table, the mean is at z = 0 and the standard deviation is equal to 1. 


z-score               area to the left of

the mean                    .5
0                           .5
1.96                        .97500
-1.5                        .06681
-.5                         .30854
-.3                         .38209
-.1                         .46017    
1                           .84134
2                           .97725


when you want the area between, you subtract the smaller area from the larger area.
that's the area between.

answers to your questions are below:

Using the unit normal table, find the proportion under the standard normal curve that lies between each of the following:
(a) the mean and z = 0 equals .5 minus .5 = 0.
(b) the mean and z = 1.96 equals .97500 minus .5 = .47500.
(c) z= -1.50 and z= -1.50 equals .06681 minus .06681 = 0.
(d) z= -.30 and z= -.10 equals .46017 minus .38209 = .07808
(e) z= 1.00 and z= 2.00 equals .97725 minus .84134 = .13591