SOLUTION: Reduce the equation 4x + 3y + 20 = 0 to the normal form and find the distance of the line from the origin

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Question 1185927: Reduce the equation 4x + 3y + 20 = 0 to the normal form and find the distance of the line from the origin
Answer by ikleyn(53765) About Me  (Show Source):
You can put this solution on YOUR website!
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Reduce the equation 4x + 3y + 20 = 0 to the normal form and find the distance of the line from the origin
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There is a remarkable formula to calculate the distance from a given point to a given straight line in a coordinate plane.


    Let the straight line in a coordinate plane is defined in terms of its linear equation 

         a*x + b*y + c = 0,

    where "a", "b" and "c" are real numbers, and let P = (x%5B0%5D,y%5B0%5D) be the point in the coordinate plane. 

    Then the distance from the point P to the straight line is equal to

        d = abs%28a%2Ax%5B0%5D+%2B+b%2Ay%5B0%5D+%2B+c%29%2Fsqrt%28a%5E2+%2B+b%5E2%29.


Regarding this formula, see the lesson
    The distance from a point to a straight line in a coordinate plane
in this site.


Your straight line is 4x + 3y + 20 = 0.


Substitute the given data  a= 4, b= 3, c= 20,  x%5B0%5D = 0,  y%5B0%5D= 0  into the formula to get the distance under the question


    abs%284%2A0+%2B+3%2A0+%2B+20%29%2Fsqrt%284%5E2%2B3%5E2%29 = abs%2820%29%2Fsqrt%2825%29 = 20%2F5 = 4.     ANSWER.


Answer.  The distance from the line to the origin is 4 units.

Solved.