SOLUTION: the area of a rhombus is 140m^2 given that one of its diagonals is 16cmlong.Calculate the perimeter of the rhombus

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Question 1185847: the area of a rhombus is 140m^2 given that one of its diagonals is 16cmlong.Calculate the perimeter of the rhombus
Answer by ikleyn(52802) About Me  (Show Source):
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the area of a rhombus is 140 m^2 given that one of its diagonals is 16 cm long. Calculate the perimeter of the rhombus
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            In your post,  the area measure is given in m^2,  while the length measure is in cm.

            I do not believe that one Math problem may have such a mixture of units, so I read 140 m^2 as 140 cm^2.


Two diagonals of a rhombus bisect eqch other, are perpendicular and divide the rhombus
in four congruent right angled triangle.


The area of each of these four triangles is  140%2F4 = 35 cm^2.


One leg of each of these triangles is 8 cm.

Hence, from the formula for the area of a right angled triangle, the other leg is  %282%2A35%29%2F8 = 70%2F8 = 8.75 cm.


Then each side of the rhombus is  sqrt%288%5E2+%2B+8.5%5E2%29 = sqrt%28136.25%29 = 11.673 cm (rounded).


So the perimeter of the rhombus is  4%2Asqrt%28136.25%29 = 46.69 cm.    ANSWER

Solved.