SOLUTION: The acute angles of a right triangle have degree measures 30 and 60. If the side opposite the 60-degree angle has length 18, then what is the length of the side opposite the 30-deg

Algebra ->  Pythagorean-theorem -> SOLUTION: The acute angles of a right triangle have degree measures 30 and 60. If the side opposite the 60-degree angle has length 18, then what is the length of the side opposite the 30-deg      Log On


   



Question 1185771: The acute angles of a right triangle have degree measures 30 and 60. If the side opposite the 60-degree angle has length 18, then what is the length of the side opposite the 30-degree angle?
Found 4 solutions by josgarithmetic, ikleyn, Edwin McCravy, mccravyedwin:
Answer by josgarithmetic(39614) About Me  (Show Source):
You can put this solution on YOUR website!
Draw the triangle; it is half of an equilateral triangle.

if x is the side opposite the 30 degree angle, 2x is the side opposite the right angle;

18%5E2%2Bx%5E2=%282x%29%5E2
and you know what to do.

Answer by ikleyn(52756) About Me  (Show Source):
You can put this solution on YOUR website!
.
The acute angles of a right triangle have degree measures 30 and 60.
If the side opposite the 60-degree angle has length 18, then what is the length
of the side opposite the 30-degree angle?
~~~~~~~~~~~~~~~~~


            The setup equation,  which  @josgarithmetic proposes you to solve in his post,  IS  INCORRECT,
            and you will obtain  NOTHING  except incorrect answer and bad score,  if will follow him.

            I came to bring a correct solution to you.


Let x be the length of the side of the triangle opposite to 30-degrees angle.

Then the hypotenuse is 2x


The Pythagorean equation takes the form


    x^2 + 18^2 = (2x)^2

    x^2 + 18^2 = 4x^2

          18^2 = 4x^2 - x^2

          18^2 = 3x^2

          x^2 = 18^2/3 = 324/3 = 108

          x                    = sqrt%28108%29 = 6%2Asqrt%283%29.    ANSWER

Solved.


It is the long way to solve the problem. This way assumes that you are very beginner student,
not familiar well with the properties of the (30-60-90-degree) triangles.


More experienced students just know that the long leg of such triangle is  sqrt%283%29 times as long as the shortest leg,

so they write  x%2Asqrt%283%29 = 18,  and from this equation quickly obtain


    x = 18%2Fsqrt%283%29 = %2818%2Asqrt%283%29%29%2F3 = 6%2Asqrt%283%29,


getting the same answer, as I developed for you in the first part of my post.


Solved  (in two ways,  for your better understanding).

---------------

For your safety,   IGNORE  the post by  @josgarithmetic.


///////////////


After my notice, he changed his setup equation, simply re-wrote it from mine.



Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
I think the way this is approached in most schools today is that they are taught
 the sides of a 30-60-90 triangle are 1,√3,2, and they use ratio and proportion
to calculate the sides of triangles similar to it.

 

x%5E%22%22%2F1%5E%22%22%22%22=%22%2218%5E%22%22%2Fsqrt%283%29

Cross-multiply

sqrt%283%29%2Ax%22%22=%22%2218

x%22%22=%22%2218%2Fsqrt%283%29

Rationalize the denominator by multiplying by sqrt%283%29%2Fsqrt%283%29

x%22%22=%22%2218%2Fsqrt%283%29%22%22%2A%22%22sqrt%283%29%2Fsqrt%283%29

x%22%22=%22%22%2818sqrt%283%29%29%2F3

x%22%22=%22%226sqrt%283%29

Edwin



Answer by mccravyedwin(405) About Me  (Show Source):