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| Question 1185771:  The acute angles of a right triangle have degree measures 30 and 60. If the side opposite the 60-degree angle has length 18, then what is the length of the side opposite the 30-degree angle?
 Found 4 solutions by  josgarithmetic, ikleyn, Edwin McCravy, mccravyedwin:
 Answer by josgarithmetic(39630)
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You can put this solution on YOUR website! Draw the triangle; it is half of an equilateral triangle. 
 if x is the side opposite the 30 degree angle, 2x is the side opposite the right angle;
 
 
  and you know what to do.
Answer by ikleyn(52879)
      (Show Source): 
You can put this solution on YOUR website! . The acute angles of a right triangle have degree measures 30 and 60.
 If the side opposite the 60-degree angle has length 18, then what is the length
 of the side opposite the 30-degree angle?
 ~~~~~~~~~~~~~~~~~
 
 
 The setup equation,  which  @josgarithmetic proposes you to solve in his post,  IS  INCORRECT,
 and you will obtain  NOTHING  except incorrect answer and bad score,  if will follow him.
 
 I came to bring a correct solution to you.
 
 
 
 
Let x be the length of the side of the triangle opposite to 30-degrees angle.
Then the hypotenuse is 2x
The Pythagorean equation takes the form
    x^2 + 18^2 = (2x)^2
    x^2 + 18^2 = 4x^2
          18^2 = 4x^2 - x^2
          18^2 = 3x^2
          x^2 = 18^2/3 = 324/3 = 108
          x                    =  =  .    ANSWERSolved.
 
 
 It is the long way to solve the problem.  This way assumes that you are very beginner student,
 not familiar well with the properties of the (30-60-90-degree) triangles.
 
 
 
 
More experienced students just know that the long leg of such triangle is   times as long as the shortest leg,
so they write  = 18,  and from this equation quickly obtain
    x =  =  =  ,
getting the same answer, as I developed for you in the first part of my post. 
 Solved  (in two ways,  for your better understanding).
 
 ---------------
 
 For your safety,   IGNORE  the post by  @josgarithmetic.
 
 
 ///////////////
 
 
 After my notice, he changed his setup equation, simply re-wrote it from mine.
 
 
 
Answer by Edwin McCravy(20064)
      (Show Source): Answer by mccravyedwin(409)
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