SOLUTION: Find an equation of the circle with center at (-3,-3)that is the tangent to the y-axis in form of (x-A)^2+(y-B)^2=C where A,B,C are constants than A is: B: C:

Algebra ->  Rational-functions -> SOLUTION: Find an equation of the circle with center at (-3,-3)that is the tangent to the y-axis in form of (x-A)^2+(y-B)^2=C where A,B,C are constants than A is: B: C:       Log On


   

Question 1185664: Find an equation of the circle with center at (-3,-3)that is the tangent to the y-axis in form of (x-A)^2+(y-B)^2=C where A,B,C are constants than A is: B: C:

Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
Your equation form, %28x-A%29%5E2%2B%28y-B%29%5E2=C, is for center point of circle at (A, B), and radius of size sqrt%28C%29.


Radius would be size 3. Do a sketch and this is easier to see.
3%2A3=9

%28x%2B3%29%5E2%2B%28y%2B3%29%5E2=9