SOLUTION: A gardener buys a package of seeds. Seventy-four percent of seeds of this type germinate. The gardener plants 100 seeds. Approximate the probability that 76 or more seeds germi

The situation is a binomial experiment.

The number of trials is 100.  The individual probability of success in each individual trial is 0.74.


So, formally there are standard formulas for binomial distribution, but the Math does not 
recommend to use them, because the formulas include high degree exponents and too great binomial
coefficients.  Instead, there is another, very effective and standard approach on solving such problems.


This approach is to use an appropriate normal distribution as an approximation to the Binomial distribution.


The relevant normal distribution has the mean  m = n*p = 100*0.74 = 74
and the standard deviation  S =  =  = 4.386342.



This normal curve covers all 100 seeds on the horizontal axis, and we should take the area under
this normal curve on the right of the threshold value of 76.


A convenient tool for it is to use the standard function  normcdf (which means Cumulative Distribution Function
for normal distribution).  This function is in any regular calculator like TI-83/84.


So, you write/print in your calculator

                 z1     z2   mean    SD        <<<---===  formatting pattern.
    P = normcdf(75.5,  9999,  74,  4.386342)


Here z1 = 75.5  stands for 76 and presents the continuing correction;  z2 stand for infinity on the horizontal axis,
mean is the mean and SD is the standard deviation.


Then the function will return the probability, which you are looking for: P = 0.3662.


It is the ANSWER to the problem's question  P = 0.3662, obtained with the normal distribution approximation.