SOLUTION: The area of a parallelogram is 88 in2. One of the diagonals measures 12 in. and one side measures 8 in. a)Find the length of the other side. b)Find the length of the other diagon

Algebra ->  Polygons -> SOLUTION: The area of a parallelogram is 88 in2. One of the diagonals measures 12 in. and one side measures 8 in. a)Find the length of the other side. b)Find the length of the other diagon      Log On


   

Question 1185595: The area of a parallelogram is 88 in2. One of the diagonals measures 12 in. and one side measures 8 in.
a)Find the length of the other side.
b)Find the length of the other diagonal.
c)Find the altitude to the longer side of the parallelogram
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


Parallelogram with area 88 and one side (AB) 8, so altitude (DE) is 88/8=11; one diagonal (the short one, BD) is 12.



a) Find the length of the other side (y).

(1) Use the Pythagorean Theorem in triangle BED to find x ;
(2) calculate 8-x (AE);
(3) Use the Pythagorean Theorem in triangle AED to find y.

b) Find the length of the other diagonal (AC).

Use the Pythagorean Theorem in triangle AFC to find z.

c) Find the altitude to the longer side of the parallelogram.

It's the area 88, divided by the length of the other side, y.