SOLUTION: Find the inverse Laplace transform of F(s)=e^(−9s)/(s^2+0s−9) (Use step(t-c) for u(t).) f(t)= My answer 1/6e^(-3(t-9))(e^(6(t-9))-1)(t-9) wrong

Algebra ->  Inverses -> SOLUTION: Find the inverse Laplace transform of F(s)=e^(−9s)/(s^2+0s−9) (Use step(t-c) for u(t).) f(t)= My answer 1/6e^(-3(t-9))(e^(6(t-9))-1)(t-9) wrong      Log On


   



Question 1185370: Find the inverse Laplace transform of
F(s)=e^(−9s)/(s^2+0s−9)
(Use step(t-c) for u(t).)
f(t)=
My answer 1/6e^(-3(t-9))(e^(6(t-9))-1)(t-9) wrong

Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!

It is known that .

===> , where H(t) is the Heaviside step function.