SOLUTION: Suppose that 30% of all voters prefer Candidate A.
If 6 people are chosen at random for a poll, what is the probability that fewer than 5 of them favor Candidate A?
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-> SOLUTION: Suppose that 30% of all voters prefer Candidate A.
If 6 people are chosen at random for a poll, what is the probability that fewer than 5 of them favor Candidate A?
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Question 1185310: Suppose that 30% of all voters prefer Candidate A.
If 6 people are chosen at random for a poll, what is the probability that fewer than 5 of them favor Candidate A?
Probability =
(Please show your answer to 4 decimal places) Found 2 solutions by ikleyn, Edwin McCravy:Answer by ikleyn(52832) (Show Source):
You can put this solution on YOUR website! .
Suppose that 30% of all voters prefer Candidate A.
If 6 people are chosen at random for a poll, what is the probability that fewer than 5 of them favor Candidate A?
Probability =
(Please show your answer to 4 decimal places)
~~~~~~~~~~~~~~~~~
It is a binomial distribution probability problem.
- number of trials n = 6;
- number of success trials k <= 4;
- Probability of success on a single trial p = 0.30.
We need calculate P(n=6; k<=4; p=0.3).
To facilitate calculations, I use an appropriate online (free of charge) calculator at this web-site
https://stattrek.com/online-calculator/binomial.aspx
It provides nice instructions and a convenient input and output for all relevant options/cases.
P(n=6; k<=4; p=0.3) = 0.989065, or 0.9891 (rounded). ANSWER
Most students in most schools in America are required to have a TI-84 graphing
calculator.
You must interpret "fewer than 5" as "4 or fewer".
Press: on clear
Press: 2nd vars
Use the down arrow to scroll to B:binomcdf(
Press: enter
Make the next screen read
binomcdf
trials:6
p:0.30
x value:4
Paste
Use the down arrow key to scroll to highlight: Paste
Press: enter
You will see on the screen
binomcdf(6,0.30,4)
Press: enter
Read the answer 0.989065, round to 0.9891.
Edwin