SOLUTION: The product of two consecutive odd integers is 63.Find the numbers

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Question 1185240: The product of two consecutive odd integers is 63.Find the numbers

Found 2 solutions by Theo, Alan3354:
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
let x be one of the odd integers.
then x + 2 would be another of the odd integers.

their product is 63.

you get x * (x + 2) = 63

simplify to get:

x^2 + 2x = 63

subtract 63 from both side of this equation to get:

x^2 + 2x - 63 = 0

factor this quadratic equation to get:

(x + 9) * (x - 7) = 0

set each factor to 0 and solve for x to get:

x = -9 or x = 7

when x = 7, the original equation becomes x * (x + 2) = 63 which becomes:
7 * 9 = 63 which is true.

when x = -9, the original equation becomes -9 * (-9 + 2) which becomes:
-9 * -7 = 63 which is also true.

the value of x can be either -9 or 7.

unless you had a restriction that the numbers had to be negative or positive, either answer is good.



Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The product of two consecutive odd integers is 63.Find the numbers
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sqrt%2863%29 =~ 8
---> 7 & 9