SOLUTION: A scientist has two solutions, which she has labeled Solution A ad Solution B. Each contains salt. She knows that Solution A is 60% salt and Solution B is 90% salt. She wants to ob
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Question 1185163: A scientist has two solutions, which she has labeled Solution A ad Solution B. Each contains salt. She knows that Solution A is 60% salt and Solution B is 90% salt. She wants to obtain 90 ounces of a mixture that is 65% salt. How many ounces of each solution should she use? Found 2 solutions by Alan3354, greenestamps:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! A scientist has two solutions, which she has labeled Solution A ad Solution B. Each contains salt. She knows that Solution A is 60% salt and Solution B is 90% salt. She wants to obtain 90 ounces of a mixture that is 65% salt. How many ounces of each solution should she use?
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Ignoring the fact that the concentrations are not realistic:
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x = amount of 60% mixture
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x*60 + (90-x)*90 = 90*65
Solve for x
etc
Also ignoring the fact that the given salt concentrations are impossible....
Here is a quick and easy way to solve 2-part "mixture" problems like this without formal algebra.
(1) Picture the three percentages 60, 65, and 90 on a number line and observe/calculate that 65% is 1/6 of the way from 60% to 90%.
(2) That means 1/6 of the mixture should be the 90% solution.
ANSWER: 1/6 of 90 ounces, or 15 ounces, of the 90% solution; the other 75 ounces of the 60% solution.
