SOLUTION: A ladder is 25 cm long leans against a vertical wall so that the base of the ladder is 7 m from the foot of the wall. If the top of the ladder slides 4 m down the wall, by how

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Question 1185051: A ladder is 25 cm long leans against a vertical wall so that the base of the ladder
is 7 m from the foot of the wall. If the top of the ladder slides 4 m down the wall,
by how many meters will the base of the ladder move away from the foot of the
wall?

Answer by ikleyn(52786) About Me  (Show Source):
You can put this solution on YOUR website!
.
A ladder is 25 cross%28cm%29 meters long leans against a vertical wall so that the base of the ladder
is 7 m from the foot of the wall. If the top of the ladder slides 4 m down the wall,
by how many meters will the base of the ladder move away from the foot of the wall?
~~~~~~~~~~~~~~~~~~~~~~

In this problem, you have two right angled triangles, both with the hypotenuse of 25 meters, 
which represents the ladder.


In the first ladder's position, horizontal leg is 7 meters; hence, vertical leg is

    sqrt%2825%5E2-7%5E2%29 = sqrt%28576%29 = 24 meters long.



When the ladder changes his position, sliding vertically  4 meters down, new vertical leg is 24 - 4 = 20 meters long.


Hence, new horizontal leg is  sqrt%2825%5E2+-+20%5E2%29 = sqrt%28225%29 = 15 meters long.


It is the new position of the base of the ladder.


So, we just solved the problem and obtained the ANSWER: the base of the ladder will move by 15 - 7 = 8 meters.

Solved.