SOLUTION: The pool has a width of x feet. The length of the pool is 2 feet more than the width. The depth of the pool is 4 feet less than twice the width. Given the pool's volume in cubi

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: The pool has a width of x feet. The length of the pool is 2 feet more than the width. The depth of the pool is 4 feet less than twice the width. Given the pool's volume in cubi      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1185017: The pool has a width of x feet. The length of the pool is 2 feet more than the width. The depth of the pool is 4 feet less than twice the width.
Given the pool's volume in cubic feet is 24 times its width in linear feet, what is the depth of the pool?

Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


x = width
x+2 = length
2x-4 = depth

The volume in cubic feet is 24 times the width in feet:

x%28x%2B2%29%282x-4%29=24
x%28x%2B2%29%28x%29%28x-2%29=24
2x%28x%5E2-4%29=24
2x%5E3-8x=24x
2x%5E3-32x=0
2x%28x%5E2-16%29=0

x = 4 or x=-4; obviously -4 makes no sense.

ANSWER: the depth of the pool is 2x-4 = 4 feet.

Note the "pool" is not very practical -- its dimensions are 4x6 feet and 4 feet deep....