SOLUTION: Bryan baked a total of 1060 chocolate puffs and strawberry puffs. After giving away an equal number of both types of puffs, he was left with 2/7 of the chocolate puffs and 1/5 of t

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: Bryan baked a total of 1060 chocolate puffs and strawberry puffs. After giving away an equal number of both types of puffs, he was left with 2/7 of the chocolate puffs and 1/5 of t      Log On


   



Question 1184949: Bryan baked a total of 1060 chocolate puffs and strawberry puffs. After giving away an equal number of both types of puffs, he was left with 2/7 of the chocolate puffs and 1/5 of the strawberry puffs. What was the total number of puffs left?
Found 3 solutions by josgarithmetic, ikleyn, greenestamps:
Answer by josgarithmetic(39630) About Me  (Show Source):
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c of the chocolate puffs
w of the strawberry puffs

c%2Bw=1060

Gave away p number of puffs of each kind
c-p of the chocolate kept
w-p of the strawberry kept


system%28c-p=%282%2F7%29c%2Cw-p=w%2F5%2Cc%2Bw=1060%29


system%287c-7p=2c%2C5w-5p=w%2Cc%2Bw=1060%29

system%285c-7p=0%2C4w-5p=0%2Cc%2Bw=1060%29


Use E1 and E2 to equation expressions for p, and have c=28w%2F25

Using substitution from
c%2Bw=1060

28w%2F25%2Bw=1060
.
.
highlight_green%28w=500%29
This means c=1060-500
highlight_green%28c=560%29


p=%284%2F5%29w
highlight_green%28p=400%29


How many puffs remain?
highlight%281060-2%2A400%29

Answer by ikleyn(52890) About Me  (Show Source):
You can put this solution on YOUR website!
.
Bryan baked a total of 1060 chocolate puffs and strawberry puffs.
After giving away an equal number of both types of puffs, he was left with 2/7 of the chocolate puffs
and 1/5 of the strawberry puffs. What was the total number of puffs left?
~~~~~~~~~~~~~~~~~


            When I solve such problems,  I always try to find the simplest way to solve - - - and the best way to teach.

            Regarding this problem,  it can be easily solved using two simple equations instead of three;
            this way is simpler and,  THEREFORE,  is more preferable.


Let  c  be the number of chocolate puffs, and

let  w  be the number of strawberry puffs.


The total was 1600 puffs, which gives you first equation

    c + w = 1600          (1)


After giving away, Bryan was left with 2/7 of the chocolate  puffs; hence, he gave away %285%2F7%29c chocolate puffs.

                   He    was left with 1/5 of the strawberry puffs; hence, he gave away %284%2F5%29w strawberry puffs.


He gave away equal number of both types of puffs; it gives you second equation

    %285%2F7%29c = %284%2F5%29w.     (2)


Multiply equation (2) by 35 (both sides).  You will get then

    25c = 28w.            (3)


Now you have the system of two equations (1) and (3).


From (1), express  c = 1060-w  and substitute it to equation (3).  You will get

    25*(1060-w) = 28w

    25*1060 - 25w = 28w

    25*1060 = 28w + 25w

       w    = %2825%2A1060%29%2F%2828%2B25%29 = 500.


So, originally, there were 500 strawberry puffs  and  1060-500 = 560 chocolate puffs.


Hence, the total number of puffs left was  %282%2F7%29%2A560 + %281%2F5%29%2A500 = 2*80 + 100 = 260.    ANSWER

Solved and thoroughly explained.



Answer by greenestamps(13209) About Me  (Show Source):
You can put this solution on YOUR website!


Let x be the number of chocolate puffs
Then 1060-x is the number of strawberry puffs

After giving away equal numbers of both, he was left with 2/7 of the chocolate puffs and 1/5 of the strawberry puffs. So 5/7 of the chocolate puffs is the same number as 4/5 of the strawberry puffs:

%285%2F7%29%28x%29=%284%2F5%29%281060-x%29

Multiply by the least common denominator (5*7=35) to clear fractions:

25x=28%281060-x%29
25x=28%281060%29-28x
53x=28%281060%29
x=28%2820%29+=+560

So he baked 560 chocolate puffs and 1060-560=500 strawberry puffs.

After giving some away, he was left with 2/7 of the chocolate puffs and 1/5 of the strawberry puffs.

(2/7)560=160
(1/5)500=100

ANSWER: The total number of puffs left was 160+100=260