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Question 1184929: Find the equation of the line with equal intercepts and passing through the point ( -4, 3/2).
Found 3 solutions by josgarithmetic, ikleyn, greenestamps:
Answer by josgarithmetic(39617)   (Show Source):
Answer by ikleyn(52786)  (Show Source):
You can put this solution on YOUR website! .
Find the equation of the line with equal intercepts and passing through the point ( -4, 3/2).
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Since x-intercept is equal to y-intercept, it means that the straight line has an equation of the form
x + y = C,
for some constant C. In particular, the slope of such straight line is -1.
To find the value of the constant C in equation (1), substitute the coordinates x= -4 and y= 3/2
of the given point into the equation. You will get then
C = -4 + 3/2 = -2.5.
Therefore, the final form of the equation is
x + y = -2.5. ANSWER
Solved, answered and explained.
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In his response, @josgarithmetic incorrectly treats the condition of equality of intercepts,
therefore, his "solution" is W R O N G.
For your safety, IGNORE his post.
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After seeing my response, @josgarithmetic changed everything in his post, replaced and re-wrote it, following to my solution..
Answer by greenestamps(13200)  (Show Source):
You can put this solution on YOUR website!
If the line has equal x- and y-intercepts, then the slope of the line is -1.
Use that slope and the given point to find the equation.
y-1.5=-1(x+4)
y-1.5=-x-4
y=-x-2.5
ANSWER: (slope-intercept form) y = -x-2.5
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