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Question 1184871: If nine men take 15 days to assemble 18 machines, how many days will it take 20 men to assemble 60 machines?
Clue: This problem is a combination of direct and indirect relations. To deal with this problem, ask yourself how the variable M(men) varies with the respected D(days); that I, will more men require more days or will more men require less days to do the job? How about M and C(machines)? Will more men produce more machines or more men produce less machines?
Show your complete solution.
Answer by greenestamps(13200)   (Show Source):
You can put this solution on YOUR website!
(1) Given: 9 men, 15 days, 18 machines assembled.
(2) 20 men instead of 9
The number of men increases by a factor of 20/9; the amount of time required decreases by a factor of 20/9
15/(20/9)=15*(9/20)=135/20=27/4
20 men, 27/4 days, 18 machines
(3) 60 machines instead of 18
The number of machines to be assembled increases by a factor of 60/18=10/3; the amount of time required increases by that same factor
(27/4)*(10/3)=270/12=45/2
20 men, 45/2 days, 60 machines
ANSWER: 45/2 days, or 22.5 days, for 20 men to assemble 60 machines
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