SOLUTION: The units digit of a two-digit is 5 more than the tens digit. If the digits are reversed and the new number is divided by the original the quotient is 2 and the remainder is 7. Wha

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: The units digit of a two-digit is 5 more than the tens digit. If the digits are reversed and the new number is divided by the original the quotient is 2 and the remainder is 7. Wha      Log On


   



Question 1184835: The units digit of a two-digit is 5 more than the tens digit. If the digits are reversed and the new number is divided by the original the quotient is 2 and the remainder is 7. What is the original number?
Answer by greenestamps(13215) About Me  (Show Source):
You can put this solution on YOUR website!


Clearly the problem is most easily solved by trial and error....

tens digit 1; the number is 16; 61/16 is not 2 remainder 7
tens digit 2; the number is 27; 72/27 is not 2 remainder 7
tens digit 3; the number is 38; 83/38 IS 2 remainder 7

ANSWER: 38

Algebraically....

Let the tens digit be x
Then the units digit is x+5

The original number is 10x%2B%28x%2B5%29=11x%2B5
The number with the digits reversed is 10%28x%2B5%29%2Bx=11x%2B50

The new number divided by the original number gives quotient 2 and remainder 7:

%2811x%2B50%29%2F%2811x%2B5%29=2%2B7%2F%2811x%2B5%29
11x%2B50=2%2811x%2B5%29%2B7
11x%2B50=22x%2B17
33=11x
x=3

The tens digit is x=3; the units digit is x+5=8

ANSWER: 38