SOLUTION: someone thinks he can shoot an arrow as high as the Willis Tower in Chicago (443 m high). (a) at what velocity would the arrow have to be released at ground level? (b) how long wou

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Question 1184744: someone thinks he can shoot an arrow as high as the Willis Tower in Chicago (443 m high). (a) at what velocity would the arrow have to be released at ground level? (b) how long would the ascent take?
Answer by ikleyn(52803) About Me  (Show Source):
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someone thinks he can shoot an arrow as high as the Willis Tower in Chicago (443 m high).
(a) at what velocity would the arrow have to be released at ground level?
(b) how long would the ascent take?
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(a)  The general formula to calculate the required initial vertical velocity of ascent  " v "  is


         v = sqrt%282gh%29,


     where h is the maximum height in meters, g is the gravity acceleration g = 9.81 m/s^2.


     For h = 443 meters (your example)


         v = sqrt%282%2A9.81%2A443%29 = 93.229 m/s.




(b)  For the ascent time, use the formula  and get the answer


         t = sqrt%28%282h%29%2Fg%29 = sqrt%28%282%2A443%29%2F9.81%29 = 9.5 seconds  (rounded).

Solved, answered and explained.