SOLUTION: An arch is in the form of a semiellipse. It is 48 ft wide at the base and has a
height of 20ft. How wide is the arch at a height of 10 ft above the base?
Algebra ->
Quadratic-relations-and-conic-sections
-> SOLUTION: An arch is in the form of a semiellipse. It is 48 ft wide at the base and has a
height of 20ft. How wide is the arch at a height of 10 ft above the base?
Log On
Question 1184728: An arch is in the form of a semiellipse. It is 48 ft wide at the base and has a
height of 20ft. How wide is the arch at a height of 10 ft above the base? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! An arch is in the form of a semiellipse. It is 48 ft wide at the base and has a
height of 20ft. How wide is the arch at a height of 10 ft above the base?
================================
Equation of the ellipse is (center at the Origin)
---
At y = 10:
x = ~20.78 (each side of the Origin)
Width = ~ 41.57 feet