SOLUTION: given that log2 = 0.3010, log3= 0.4771 and log7= 0.8451 evaluate 1.log(14/3) 2.log (7/2)
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-> SOLUTION: given that log2 = 0.3010, log3= 0.4771 and log7= 0.8451 evaluate 1.log(14/3) 2.log (7/2)
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Question 1184680
:
given that log2 = 0.3010, log3= 0.4771 and log7= 0.8451
evaluate
1.log(14/3)
2.log (7/2)
Answer by
Alan3354(69443)
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given that log2 = 0.3010, log3= 0.4771 and log7= 0.8451
evaluate
1.log(14/3) = log(2) + log(7) - log(3)
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2.log (7/2) = log(7) - log(2)