Here are the 36 dice rolls with 2 dice:
(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)
Here are the positive differences of those above:
0 1 2 3 4 5
1 0 1 2 3 4
2 1 0 1 2 3
3 2 1 0 1 2
4 3 2 1 0 1
5 4 3 2 1 0
$X P(X) E(X)
------------------------------
$0 6/36 0
$1 10/36 10/36
$2 8/36 16/36
$3 6/36 18/36
$4 4/36 16/36
$5 2/36 2/36
------------------------------
total expectation = 62/36 = 31/18 = $1.72222...
No. it isn't fair, because the expected value of the
game is $1.72222... minus $5.00 = -$3.27777...
So you expect to average losing about $3.28 per game
if you played the game many times.
Edwin