SOLUTION: If Sally can paint a house in 4 hours, and John can paint the same house in 6 hours, how long will it take for both of them to paint the house together.
I know that Sally can pa
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-> SOLUTION: If Sally can paint a house in 4 hours, and John can paint the same house in 6 hours, how long will it take for both of them to paint the house together.
I know that Sally can pa
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Question 118453: If Sally can paint a house in 4 hours, and John can paint the same house in 6 hours, how long will it take for both of them to paint the house together.
I know that Sally can paint a house 2/3 faster than John. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! If Sally can paint a house in 4 hours, and John can paint the same house in 6 hours, how long will it take for both of them to paint the house together.
:
Let t = time required when painting together
:
Let the completed job = 1
:
A simple equation: + = 1
;
Multiply equation by 12 to get rid of the denominators:
12* + 12* = 12(1)
:
Cancel out the denominators and you have:
3t + 2t = 12
:
5t = 12
:
t = 12/5
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t = 2.4 hrs working together (and not fooling around)
:
:
Check our solution in the original equation: + =
.6 + .4 = 1, confirms out solution
