SOLUTION: Given that f(x) = 2x^2 + x - 3,write f(x) in the form a(x+b)^2 + c,where a,b and c are constants. Sketch the graph of y= |f(x)|
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-> SOLUTION: Given that f(x) = 2x^2 + x - 3,write f(x) in the form a(x+b)^2 + c,where a,b and c are constants. Sketch the graph of y= |f(x)|
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Question 1184513: Given that f(x) = 2x^2 + x - 3,write f(x) in the form a(x+b)^2 + c,where a,b and c are constants. Sketch the graph of y= |f(x)| Found 2 solutions by Edwin McCravy, mccravyedwin:Answer by Edwin McCravy(20055) (Show Source):
Factor 2 out of the first two terms
To the side take half of the coefficient of x, which is 1/2 of 1/2 or 1/4.
Square it. Get (1/4)2=1/16.
Add and subtract 1/16 inside the parentheses (which amounts to adding zero)
Factor the first three terms inside the parentheses
Distribute the 2:
That's in the form , a=2, b=1/4, c=-25/8
Edwin
