SOLUTION: Find the value of “a” for which the graph of the first equation is perpendicular to the graph of the second equation. Problem: y=a/3x-6; 4x+2y=6

Algebra ->  Linear-equations -> SOLUTION: Find the value of “a” for which the graph of the first equation is perpendicular to the graph of the second equation. Problem: y=a/3x-6; 4x+2y=6      Log On


   

Question 1184510: Find the value of “a” for which the graph of the first equation is perpendicular to the graph of the second equation.
Problem: y=a/3x-6; 4x+2y=6
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Under the assumption the first equation has a misprint,
The given equations are as system%28y=%28a%2F3%29x-6%2C4x%2B2y=6%29 .

system%28y=%28a%2F3%29x-6%2C2x%2By=3%29

system%28y=%28a%2F3%29x-6%2Cy=-2x%2B3%29

If perpendicular, then %28a%2F3%29%28-2%29=-1
%28a%2F3%29%2A2=1
highlight%28a=3%2F2%29