SOLUTION: Tim and Ron have some sweets each. If Tim eat 8 has of his sweets, the ratio of the number of sweets Tim has to the number of sweets Ron has becomes have 2:7. If Ron eats 8 of his
Algebra ->
Percentage-and-ratio-word-problems
-> SOLUTION: Tim and Ron have some sweets each. If Tim eat 8 has of his sweets, the ratio of the number of sweets Tim has to the number of sweets Ron has becomes have 2:7. If Ron eats 8 of his
Log On
Question 1184391: Tim and Ron have some sweets each. If Tim eat 8 has of his sweets, the ratio of the number of sweets Tim has to the number of sweets Ron has becomes have 2:7. If Ron eats 8 of his sweets, Tim will have 80% as many sweets as Ron. How many sweets do they have altogether? Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! (T-8)/R=2/7
T/(R-8)=4/5
cross-multiply each
2R=7T-56
4R-32=5T
rewrite
2R-7T=-56
4R-5T=32
-4R+14T=+112, multiplying top by -2
so 9T=144
T=16 for Tim
8/R=2/7
2R=56
R=28 for Ron
Tim has 16, Ron has 28
Together they have 44 ANSWER
