SOLUTION: A hyperbola has vertices (±5,0) and one focus at (6,0). What is the equation of the hyperbola in standard form?

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Question 1184367: A hyperbola has vertices (±5,0) and one focus at (6,0). What is the equation of the hyperbola in standard form?
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

vertices: ( 5,0) ,( 5,0)
=>major (transverse) axis length: 2a=10 =>a=5
one focus at (6,0)=> other focus is at (-6,0) and c=6
=> center: (0,0)
then, b%5E2=c%5E2-a%5E2
b%5E2=6%5E2-5%5E2
b%5E2=36-25
b%5E2=11
and, the equation of the hyperbola is:
x%5E2%2Fa%5E2-y%5E2%2Fb%5E2=1
x%5E2%2F25-y%5E2%2F11=1