SOLUTION: 1) 2^5/2 - 2^3/2=? This is the First One
2) x^2-x-6/x^2-4=? This is the Second One
Can Plz send me solution To this Problems it is really Urgent
Algebra ->
Rational-functions
-> SOLUTION: 1) 2^5/2 - 2^3/2=? This is the First One
2) x^2-x-6/x^2-4=? This is the Second One
Can Plz send me solution To this Problems it is really Urgent
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2) x^2-x-6/x^2-4=? This is the Second One
Can Plz send me solution To this Problems it is really Urgent Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 1) 2^5/2 - 2^3/2=? This is the First One
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Comment: What you have posted can be interpreted in two ways:
1st way: = 32/2 - 8/2 = 16 - 4 = 12
2nd way: (2^(3/2))(2-1) = 2^(3/2)
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2) x^2-x-6/x^2-4
= [(x-3)(x+2)]/[(x-2)(x+2)]
= (x-3)/(x-2)
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Cheers,
Stan H.
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