Question 1184276: The sum of three numbers is 114. The first number is 6 less than the third. The second number is 4 times the third. What are the numbers? Found 2 solutions by MathLover1, MathTherapy:Answer by MathLover1(20850) (Show Source):
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The sum of three numbers is 114. The first number is 6 less than the third. The second number is 4 times the third. What are the numbers?
let three numbers be ,, and
if the sum of three numbers is , we have
.......eq.1
if the first number is less than the third, we have
....eq.2
if the second number is times the third, we have
....eq.3
go to
.......eq.1, substitute and ........solve for .......divide by
then
and
so, your numbers are: ,, and
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The sum of three numbers is 114. The first number is 6 less than the third. The second number is 4 times the third. What are the numbers?
Let 3rd number be T
Then 1st is: T - 6, and 2nd = 4T
We then get: T + T - 6 + 4T = 114
6T = 114 + 6
6T = 120
3rd number, or
1st number:
2nd number: