SOLUTION: Using the 95% confidence level and the writing scores 91,91, 94, 91, 90, 81, 84, 91, 92, 91, 91, 98, 94, 91, 85, 91 you would expect the upper end of the confidence interval to be

Algebra ->  Statistics  -> Confidence-intervals -> SOLUTION: Using the 95% confidence level and the writing scores 91,91, 94, 91, 90, 81, 84, 91, 92, 91, 91, 98, 94, 91, 85, 91 you would expect the upper end of the confidence interval to be       Log On


   

Question 1184232: Using the 95% confidence level and the writing scores 91,91, 94, 91, 90, 81, 84, 91, 92, 91, 91, 98, 94, 91, 85, 91 you would expect the upper end of the confidence interval to be approximately what value?
Answer by Edwin McCravy(20059) About Me  (Show Source):
You can put this solution on YOUR website!
91, 91, 94, 91, 
90, 81, 84, 91, 
92, 91, 91, 98, 
94, 91, 85, 91

On your TI-84

Press STAT
Press 1
Enter all 16 numbers above into L1
When you have them all entered,
Press STAT again
Press the right arrow key to highlight CALC
Press 1:1-Var Stats
The screen reads

         1-Var Stats
     List:L1
     FreqList:
     Calculate    

Press the down arrow key twice to highlight Calculate
Press ENTER

Read
         1-Var Stats
      x̄=90.375
      Σx=1446
      Σx2=130930
      Sx=4.064070209
      σx=3.93501906 
      n=16      

That shows the data that's been calculated from L1 but you don't have to
enter it, because it's automatically entered on the next screen.

Press STAT again
Press the right arrow key to highlight TESTS
Press 7:ZInterval
Make sure the screen reads like this, use the arrow key to highlight Data,
not Stats.  Make sure the C-level reads 0.95

    Z-Interval
Inpt:Data Stats
σ:24.1
List:L1
Freq:1
C-Level:0.95   
Calculate

Highlight Calculate with the down arrow key

Press ENTER
(78.566,102.18)
x̄=90.375
Sx=4.064070209
n=16

The confidence interval is 78.566 < x < 102.18

So the expected upper end of it is 102.18.

Edwin