SOLUTION: A carpenter can construct book cases at a cost of P400 each. If
the carpenter sells the book cases for 𝑥 dollars each, it is
estimated that 300 − 2𝑥 book cases will be so
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-> SOLUTION: A carpenter can construct book cases at a cost of P400 each. If
the carpenter sells the book cases for 𝑥 dollars each, it is
estimated that 300 − 2𝑥 book cases will be so
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Question 1184191: A carpenter can construct book cases at a cost of P400 each. If
the carpenter sells the book cases for 𝑥 dollars each, it is
estimated that 300 − 2𝑥 book cases will be sold per month.
Express the number of dollars in the carpenter’s monthly
profit as a function of 𝑥. Answer by ikleyn(52786) (Show Source):
You can put this solution on YOUR website! .
A carpenter can construct book cases at a cost of $400 each. If
the carpenter sells the book cases for x dollars each, it is
estimated that 300 − 2x book cases will be sold per month.
Express the number of dollars in the carpenter’s monthly
profit as a function of x.
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Notice that in your post I replaced P400 by $400.
The monthly profit is the product of the profit per single book case
multiplied by the number of the sold book cases
PROFIT = P = (x-400)*(300-2x) dollars.
You can equivalently present it in the form
P = 300x - 2x^2 - 120000 + 800x dollars
or in the form
P = -2x^2 + 1100x - 120000 dollars.
