SOLUTION: Five people gather for a dinner party. Compute the probability that no two of them
have the same birthday. (Hint: use 365 days for a year).
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-> SOLUTION: Five people gather for a dinner party. Compute the probability that no two of them
have the same birthday. (Hint: use 365 days for a year).
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Question 1184147: Five people gather for a dinner party. Compute the probability that no two of them
have the same birthday. (Hint: use 365 days for a year). Answer by ikleyn(52824) (Show Source):
You can put this solution on YOUR website! .
Five people gather for a dinner party. Compute the probability that no two of them
have the same birthday. (Hint: use 365 days for a year).
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1-st person has his (or her) birthday at some day of the year.
The probability that the 2-nd person has his (or her) birthday at some other of remaining 364 days is .
The probability that the 3-rd person has his (or her) birthday at some other of remaining 363 days is .
The probability that the 4-th person has his (or her) birthday at some other of remaining 362 days is .
The probability that the 5-th person has his (or her) birthday at some other of remaining 361 days is .
The final probability is = 0.9729 (rounded). ANSWER
