SOLUTION: 3/4 of Nancy’s money is equal to 2/5 of Irene’s money. The difference in their amount of money is equal to 1/7 of Ellen’s money. Given that Ellen has $340 more than Irene,

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: 3/4 of Nancy’s money is equal to 2/5 of Irene’s money. The difference in their amount of money is equal to 1/7 of Ellen’s money. Given that Ellen has $340 more than Irene,       Log On


   



Question 1184114: 3/4 of Nancy’s money is equal to 2/5 of Irene’s money. The difference in their amount of
money is equal to 1/7 of Ellen’s money. Given that Ellen has $340 more than Irene, find the
total sum of money that the 3 girls have altogether.

Answer by ikleyn(52818) About Me  (Show Source):
You can put this solution on YOUR website!
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3/4 of Nancy’s money is equal to 2/5 of Irene’s money. The difference in their amount of
money is equal to 1/7 of Ellen’s money. Given that Ellen has $340 more than Irene, find the
total sum of money that the 3 girls have altogether.
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Let x be the amount Nancy had, in dollars.


We are given that %283%2F4%29x is equal to %282%2F5%29  of Irene's money; hence, Irene had %285%2F2%29%2A%283%2F4%29x = %2815%2F8%29x  dollars.


The difference of their money (Irene and Nancy) is  %2815%2F8%29x - x = %287%2F8%29x.


It is 1%2F7 of the Ellen's money;  hence, Ellen's money is  7%2A%287%2F8%29x = %2849%2F8%29x.


The last condition of the problems gives this equation


    Ellen - Irene = 340 dollars,   or  %2849%2F8%29x - %2815%2F8%29x = 340.


To solve, multiply all the terms by 8


    49x - 15x = 340*8

      34x     = 340*8

        x     = 10*8 = 80.


Thus Nancy had  $80;  Irene had  %2815%2F8%29x = %2815%2F8%29%2A80 = $150;  Ellen had %2849%2F8%29x = %2849%2F8%29%2A80 = $490.


ANSWER.  The total is  80 + 150 + 490 = 720 dollars.

Solved.