SOLUTION: A fruit seller had 60 kg of pears which he graded into 3 sizes A, B and C. The ratio of the mass of Grade A pears to the mass of Grade B pears to the mass of Grade C pears was 2 :
Algebra ->
Percentage-and-ratio-word-problems
-> SOLUTION: A fruit seller had 60 kg of pears which he graded into 3 sizes A, B and C. The ratio of the mass of Grade A pears to the mass of Grade B pears to the mass of Grade C pears was 2 :
Log On
Question 1184063: A fruit seller had 60 kg of pears which he graded into 3 sizes A, B and C. The ratio of the mass of Grade A pears to the mass of Grade B pears to the mass of Grade C pears was 2 : 5 : 3. There were 7 Grade B pears per kilogram. This was 2 pears more than in one kilogram of Grade A pears and 3 pears less than in one kilogram of Grade C pears. What was the ratio of the number of Grade A pears to the number of Grade B pears to the number of Grade C pears? Answer by robertb(5830) (Show Source):
You can put this solution on YOUR website!
Of the 60 kg of pears, (2/10)*60 = 12 kg is grade A, (5/10)*60 = 30 kg is grade B, and (3/10)*60 = 18 kg is grade C.
Now from the given there 5 grade A pears/kg, 7 grade B pears/kg, and 10 grade C pears/kg.
===> 5*12 = 60 grade A pears,
7*30 = 210 grade B pears, and
10*18 = 180 grade C pears.
Total number of pears is 450.
===> 60/450 = 2/15 grade A pears
210/450 = 7/15 grade B pears, and
180/450 = 6/15 grade C pears.
Therefore the ratio of the number of Grade A pears to the number of Grade B pears to the number of Grade C pears is .
