SOLUTION: If g(x) = 2x^2 + bx + 5 and g(1) = 4, what is the value of g(-1)? The correct answer is 10, but please explain.

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: If g(x) = 2x^2 + bx + 5 and g(1) = 4, what is the value of g(-1)? The correct answer is 10, but please explain.       Log On


   

Question 1184037: If g(x) = 2x^2 + bx + 5 and g(1) = 4, what is the value of g(-1)?
The correct answer is 10, but please explain.
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!
Use the g(1)=4 information to solve for b (set x=1, solve for b and re-write g(x)).

Then plug in x=-1 into g(x)