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The third angle of an isosceles triangle is 8° more than twice as large as each base angle.
Find the measure in degrees of each base angle?
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Let x be the measure of a base angle.
Then the measure of the other base angle is x, again,
and the measure of the third angle (the "vertex" angle) is 2x+8 degrees.
Since the sum of interior angles of any triangle is 180 degrees, we have this equation
x + x + (2x+8) = 180,
which implies
4x + 8 = 180,
4x = 180 - 8 = 172
x = 172/4 = 43 degrees.
ANSWER. The measure of each base angle is 43 degrees.
Solved.