SOLUTION: Please help me find the solution set to the inequality |1 - 4x^2| - |11x - 12 - 2x^2| <= 1. Thank you.

Algebra ->  Inequalities -> SOLUTION: Please help me find the solution set to the inequality |1 - 4x^2| - |11x - 12 - 2x^2| <= 1. Thank you.      Log On


   



Question 1183959: Please help me find the solution set to the inequality

|1 - 4x^2| - |11x - 12 - 2x^2| <= 1.

Thank you.

Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


By far the easiest way to find the solution set is with a graphing calculator. Graph the two functions

y=abs%281-4x%5E2%29-abs%2811x-12-2x%5E2%29 and y=1

and see where the curve is below y=1.

graph%28400%2C400%2C-10%2C2%2C-30%2C10%2Cabs%281-4x%5E2%29-abs%2811x-12-2x%5E2%29%2C1%29

Visually, the solution is the interval between about -6.6 and +1. A graphing calculator gives the approximate interval to several decimal places as (-6.566084, 1.0660844).

An exact algebraic solution requires a lot of work....

The behavior of the function on the left changes when either of the expressions in absolute value changes sign.

1-4x%5E2+=+%281-2x%29%281%2B2x%29

The behavior changes are x=-1/2 and x=1/2.

abs%281-4x%5E2%29=1-4x%5E2 on the interval (-1/2,1/2);
abs%281-4x%5E2%29=4x%5E2-1 everywhere else

11x-12-2x%5E2=-%282x%5E2-11x%2B12%29+=+-1%282x-3%29%28x-4%29

The behavior changes at x=3/2 and x=4.

abs%28-%282x%5E2-11x%2B12%29%29=-%282x%5E2-11x%2B12%29 on the interval (3/2,4);
abs%28-%282x%5E2-11x%2B12%29%29=%282x%5E2-11x%2B12%29 everywhere else

The critical points of the complete function divide the x-axis into 5 intervals on which the analysis needs to be done separately.

(1) (-infinity,-1/2)
(2) (-1/2,1/2)
(3) (1/2,3/2)
(4) (3/2,4)
(5) (4,infinity)

On intervals (1), (3), and (5),



and the inequality is

2x%5E2%2B11x-13%3C=1
2x%5E2%2B11x-14%3C=0

The quadratic formula gives the zeros of that quadratic expression as

%28-11-sqrt%28233%29%29%2F4 = -6.566084
and
%28-11%2Bsqrt%28233%29%29%2F4 = 1.066084

Note one of those solutions is in interval (1) and the other is in interval (3), so both are valid solutions; and those solutions agree with what we found with a graphing calculator.

I'll let you do the details if you want; but on intervals (2) and (4) there are no real solutions, so the results we have found are the complete answer.

ANSWER: the solution set to the inequality is from %28-11-sqrt%28233%29%29%2F4 to %28-11%2Bsqrt%28233%29%29%2F4