SOLUTION: a graduated cylinder was filled with water to the 15.0 ml mark and weighed on a balnace. It mass was27.35g. An object made of silver was [placed in the cylinder and completely subm

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: a graduated cylinder was filled with water to the 15.0 ml mark and weighed on a balnace. It mass was27.35g. An object made of silver was [placed in the cylinder and completely subm      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 118387: a graduated cylinder was filled with water to the 15.0 ml mark and weighed on a balnace. It mass was27.35g. An object made of silver was [placed in the cylinder and completely submerged in the water. The water level rose to 18.3ml. When reweighed the cylinder,water and silver object had a total mass of 62.0g.
Calculate the density of silver

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
A graduated cylinder was filled with water to the 15.0 ml mark and weighed on a balance. It's mass was 27.35 g. An object made of silver was placed in the cylinder and completely submerged in the water. The water level rose to 18.3ml. When reweighed the cylinder,water and silver object had a total mass of 62.0g.
Calculate the density of silver.
:
Mass of the silver:
62 - 27.35 = 34.65 g
:
Volume of the silver:
18.3 - 15.0 = 3.3 ml of water displaced by the silver
:
Convert ml to cu/cm;
we know that; 1 liter = 10^3 cu/cm
1 ml = 1 cm^3
therefore: 3.3 ml = 3.3 cm^3
:
Density is defined as the ratio of Mass to Volume often given as, grams/cm^3:
D = 34.65%2F3.3
D = 10.5 is the density of silver
:
Did this help?