SOLUTION: The percentage error in the measurement of the lenth of a rope was 74%. If the measurement was 35m, find the actual length of the rope to 1dp

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Question 1183843: The percentage error in the measurement of the lenth of a rope was 74%. If the measurement was 35m, find the actual length of the rope to 1dp
Found 2 solutions by ikleyn, MathLover1:
Answer by ikleyn(52890) About Me  (Show Source):
You can put this solution on YOUR website!
.

It is not possible to answer the problem's question as it is worded,

because the question is posed INCORRECTLY.


The composer of this problem deserves the lowest possible score for producing this FAKE problem.


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The solution by @MathLover1 is TOTALLY INADEQUATE.


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Technically, if the statement says that the error of the measure of the length x

is "k" percents and "m" is the measured value, it means that


    | x - m |  = 0.01*k*x.



In our case, it takes the form

   
    | x - 35 | = 0.74x.



        +----------------------------------------------------------+
        |   NOTICE the ABSOLUTE VALUE sign in this equality (!)    |
        +----------------------------------------------------------+



So, we have TWO equations for x


        (a)  x - 0.74x = 35,  which implies  0.26x = 35,   x = 35%2F0.26 = 134.6 meters (rounded),

    or  

        (b)  x + 0.74x = 35,  which implies  1.74x = 35,   x = 35%2F1.74 = 20.1 meters (rounded).



Thus you have TWO possible answers, and from the description, there is NO WAY to select one unique answer.



Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

74% =0.74
If the measurement with an error percentage was 35m, then the measurement of the length of a rope is
%2874%2F100%29L=35
L=3500%2F74
L+=+1750%2F37
L+=+47.2972972972973
L+=+47.3m