SOLUTION: Solve: |x+7| + |x-4| = 13

Algebra ->  Absolute-value -> SOLUTION: Solve: |x+7| + |x-4| = 13      Log On


   



Question 1183772: Solve: |x+7| + |x-4| = 13
Found 3 solutions by MathLover1, greenestamps, ikleyn:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Solve:
abs%28x%2B7%29+%2B+abs%28x-4%29+=+13
find positive and negative intervals
+x%2B7+%2B++x-4+=+13
+2x%2B3++=+13
+2x++=+13-3
+2x++=+10
+highlight%28x++=+5%29

+-%28x%2B7%29+-%28+x-4%29+=+13
+-x-7+-x%2B4+=+13
+-2x-3++=+13
+-2x+=+13%2B3
+-2x+=+16
+x+=+16%2F-2
+highlight%28x+=+-8%29

Answer by greenestamps(13203) About Me  (Show Source):
You can put this solution on YOUR website!


(Revised/expanded response, following comment from student....)

The solution from the other tutor arrives at the correct solution. However, the method of solution is deficient; and the limited explanation of HOW to solve the problem makes the response of little use to the student.

The function changes behavior at x=-7 and x=4; so three intervals must be examined for solutions: x less than -7, x between -7 and 4, and x greater than 4.

(1) If x is less than -7, then
x+7 is negative, so abs%28x%2B7%29=-%28x%2B7%29=-x-7
and x-4 is also negative, so abs%28x-4%29=-%28x-4%29=-x%2B4

and then the equation is
%28-x-7%29%2B%28-x%2B4%29=13
-2x-3=13
-16=2x
x=-8

(2) If x is between -7 and 4, then
x+7 is positive, so abs%28x%2B7%29=x%2B7
and x-4 is negative, so abs%28x-4%29=-%28x-4%29=-x%2B4

and then the equation is
%28x%2B7%29%2B%28-x%2B4%29=13
11=13

That equation is obviously never true, so there is no solution in the interval between -7 and 4.

(3) If x is greater than 4, then
x+7 is positive, so abs%28x%2B7%29=x%2B7
and x-4 is also positive, so abs%28x-4%29=x-4

and then the equation is
%28x%2B7%29%2B%28x-4%29=13
2x%2B3=13
2x=10
x=5

So there are two solutions: x=-8 and x=5.

Here is a graph of the two functions abs%28x%2B7%29%2Babs%28x-4%29 and 13; the two graphs intersect at x=-8 and x=5.

graph%28400%2C200%2C-10%2C10%2C-5%2C20%2Cabs%28x%2B7%29%2Babs%28x-4%29%2C13%29


Answer by ikleyn(52834) About Me  (Show Source):
You can put this solution on YOUR website!
.

At this forum, the team of the first class tutors is needed

to neutralize the errors of the rest of the tutors.