SOLUTION: A circle through P(5,9), Q(11,-3), and R(13,3). Find its equation in standard form. The perpendicular bisector of any chord of a circle will pass through the center. Thus, find th

Algebra ->  Equations -> SOLUTION: A circle through P(5,9), Q(11,-3), and R(13,3). Find its equation in standard form. The perpendicular bisector of any chord of a circle will pass through the center. Thus, find th      Log On


   



Question 1183738: A circle through P(5,9), Q(11,-3), and R(13,3). Find its equation in standard form.
The perpendicular bisector of any chord of a circle will pass through the center. Thus, find the intersection of the two perpendicular bisectors above. This will be the center C of the circle.

Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
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